Solution: nothing but pointer manipulation; check here for insertion sort.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *insertionSortList(ListNode *head) {
// IMPORTANT: Please reset any member data you declared, as
// the same Solution instance will be reused for each test case.
if(head==NULL || head->next==NULL)
return head;
ListNode* outerPre = head;
ListNode* outerCur = head->next;
while(outerCur!=NULL){
ListNode* pre = NULL;
ListNode* cur = head;
while(cur!=outerCur && cur->val<=outerCur->val){
pre=cur;
cur=cur->next;
}
if(cur->val>outerCur->val){
ListNode* tmp = outerCur->next;
outerPre->next=tmp;
if(pre==NULL){
outerCur->next = head;
head=outerCur;
outerCur=tmp;
}
else{
outerCur->next = cur;
pre->next=outerCur;
outerCur=tmp;
}
}
else{
outerPre=outerCur;
outerCur=outerCur->next;
}
}
return head;
}
};
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